https://codility.com/programmers/lessons/6-sorting/distinct/
Question:
Write a function
class Solution { public int solution(int[] A); }
that, given a zero-indexed array A consisting of N integers, returns the number of distinct values in array A.
Assume that:
A[0] = 2 A[1] = 1 A[2] = 1 A[3] = 2 A[4] = 3 A[5] = 1 the function should return 3, because there are 3 distinct values appearing in array A, namely 1, 2 and 3.
Complexity:
that, given a zero-indexed array A consisting of N integers, returns the number of distinct values in array A.
Assume that:
For example, given array A consisting of six elements such that:
- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [−1,000,000..1,000,000].
A[0] = 2 A[1] = 1 A[2] = 1 A[3] = 2 A[4] = 3 A[5] = 1 the function should return 3, because there are 3 distinct values appearing in array A, namely 1, 2 and 3.
Complexity:
Elements of input arrays can be modified.
- expected worst-case time complexity is O(N*log(N));
- expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments).
My Solution:
Notes:
1. Remember to import (for using "Arrays.sort(xxx[])")
import java.util.*;
2. Using "Arrays.sort(A)" (important)
Arrays.sort(A);
3. for counting the distinct numbers
for(int i=1; i < A.length; i++){
if(A[i] != A[i-1]){ // distinct
result++;
}
}
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